WebDec 3, 2024 · Trim blank space in database attribute in crystal report 3855 Views Follow RSS Feed Some data has blank space, i am trying to use trim in if condition if (not isnull(trim({email_id})) then "Email: " + trim({email_id}) else "No Email Entered" When email is blank, this condition works well. WebNov 8, 2011 · removing a specific character from a string. I do not have very much knowledge of programming and really need help. I am pulling reports from a field …
Crystal reports 11: How to handle or trim special characters
WebApr 23, 2024 · Trim removes whitespace-characters at the beginning and end of the string. The equivalent of the SQL SUBSTRING -function in Crystal Reports is the Mid -Function: Mid ("A003-A113-02",6,4) Share Follow edited Apr 23, 2024 at 11:33 answered Apr 23, 2024 at 8:13 MatSnow 7,242 3 21 31 I tried to use the mid function but did not return any … WebFormula : right ( {'FIELD'},instr (strreverse ( {'FIELD'}),"*")-1) Notes on the formula : {'FIELD'} represents the string field you are trying to extract specific data from. "*" represents the character in the field that indicates where you want to start. Function descriptions: right = Use this function to obtain just the right part of a string. danger of low testosterone in men
crystal reports - removing a specific character from a …
WebSep 14, 2024 · How do I remove the first character of a string in Crystal Report? Open the report in Crystal Reports. Go to View > Field Explorer. Right-click on Formula Fields and select New. Enter a name for the formula and click OK. Enter a formula similar to the one below: Mid ( {FieldName}, x) Where x is the starting position of the text that you want. WebApr 29, 2002 · 29 Apr 02 13:29. I want to remove the first three characters in a text field but can't find any formulas to do that. Help. Thanks. LMCRYER (Programmer) 29 Apr 02 … WebJun 30, 2016 · Remove last x characters leading from specific character. 684 Views. Follow. RSS Feed. Can you please help me with a formula for Crystal Reports that removes the last characters of a string, up to the semicolon? (seen from the right) So that this: Biology; 3; 3; 26. becomes this: birmingham nightlife area