Weba r ( p + q) − 1 a r ( p − q) − 1 = m n. ⇒ r 2 q = m n. ⇒ r q = m n. Now, from Now, from ( i): a ( r p − 1 × r q) = m. ⇒ a r p − 1 × m n = m. ⇒ a r p − 1 = m × n m. ⇒ a r p − 1 = m n m. Thus, the … WebIf \( p^{\text {th }}, q^{\text {th }} \), and \( r^{\text {th }} \) term of a \( \mathrm{GP}\) are again in \( \mathrm{GP}\) then \( p, q, r \), are in📲PW ...

In G.P. (p + q)^th term is m, (p - q)^th term is n, then p^th …

WebJan 7, 2024 · The exercise reads as follows: The sum of the first 5 terms in a geometric progression is 62. The 5th, 8th and 11th term of this geometric sequence are also the 1st, … WebMar 16, 2024 · In this problem we are given five values m, n, mth term, nth term, p. Our task is to Find Pth term of a GP if Mth and Nth terms are given. For a GP, we are given the values of mth term and nth term. Using these values, we need to find the Pth term of the series. Let’s take an example to understand the problem, Input how to set up google review link

If p+qth term of a G.P be m and p qth term be n, then the pth term …

WebIf the (p + q)th and (p – q)th terms of a GP are m and n respectively, find its pth term. Answer : Let, tp + q = m = Arp + q – 1 = Arp – 1rq. And. tp – q = n = Arp – q – 1 = Arp – 1r – q. We know that pth term = Arp – 1. ∴ m × n = A2r2p – 2. ⇒ Arp – … WebMar 30, 2024 · Transcript. Example 21 If pth, qth, rth and sth terms of an A.P. are in G.P, then show that (p – q), (q – r), (r – s) are also in G.P. We know that the nth term of AP is a + (n – 1)d i.e. an = a + (n – 1)d It is given that ap, aq, ar & as in GP i.e. their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in ... how to set up google scholar account